Factoring Techniques Practice Quiz with a Step-by-Step Interactive Lesson
Use the question set below to practice factoring techniques for algebra: factoring out the GCF, factoring difference of squares, recognizing perfect square trinomials, factoring trinomials (\(x^2+bx+c\) and \(ax^2+bx+c\)), factoring by grouping, and factoring completely (including repeated patterns like \(x^4-1\) and identities like \(x^3-1\)). If you want a clear method you can reuse on any problem, click Start lesson to open a step-by-step guide with worked examples and quick checks.
Answer the question set and review your mistakes at the end.
How this factoring practice works
1. Take the practice set: answer the factoring questions below.
2. Open the lesson (optional): review the factoring checklist and the most common factoring patterns.
3. Retry: return to the question set and apply the factoring strategy immediately (GCF -> patterns -> trinomials -> grouping -> final check).
What you will learn in the factoring techniques lesson
The factoring checklist (always the same order)
Step 1: GCF - factor out the greatest common factor first
Step 2: Patterns - difference of squares and perfect square trinomials
Step 3: Trinomials - factor \(x^2+bx+c\) and \(ax^2+bx+c\)
Quadratics you can factor fast
Factoring binomials like \(x^2-25\) and \(2x^2-18\)
Factoring trinomials like \(x^2+5x+6\) and \(2x^2+7x+3\)
Perfect square forms like \(9x^2-12x+4=(3x-2)^2\)
Grouping and higher-degree factoring
Factoring by grouping for four-term polynomials
Repeated patterns like difference of squares twice (example: \(x^4-1\))
Classic identities like difference of cubes \(x^3-1=(x-1)(x^2+x+1)\)
Check your work and use factoring
Factor completely and avoid "almost factored" answers
Multiply to check (your best error detector)
Use the zero product property to solve factored equations
Purpose: Learn factoring techniques you can reuse on any problem: factor out the GCF, recognize common patterns, factor trinomials (including \(ax^2+bx+c\)), factor by grouping, and factor completely with a final check.
Success criteria
Start every problem by factoring out the greatest common factor (GCF).
Recognize key patterns: difference of squares and perfect square trinomials.
Factor trinomials of the form \(x^2+bx+c\) and \(ax^2+bx+c\).
Use factoring by grouping to factor four-term polynomials.
Factor higher-degree expressions using repeated patterns (example: \(x^4-1\)).
Use identities like \(x^3-1=(x-1)(x^2+x+1)\) when they appear.
Factor completely and confirm by multiplying to check.
Use the zero product property to solve factored equations.
Key vocabulary
Factor: an expression multiplied by another expression to produce the original polynomial.
GCF: the greatest common factor shared by every term.
Binomial / Trinomial: a polynomial with 2 terms / 3 terms.
Factor completely: keep factoring until no factor can be factored further over the integers.
Zero product property: if \(AB=0\), then \(A=0\) or \(B=0\).
Quick pre-check
Pre-check 1: Which expression is fully factored over the integers?
Hint: “Fully factored” means you can’t factor any factor further using integers.
Pre-check 2: Which polynomial is a difference of squares?
Hint: A difference of squares has exactly two terms: \(a^2-b^2\).
GCF First
Step 1: Factor out the GCF
Learning goal: Start every factoring problem by pulling out the greatest common factor (GCF). This makes everything else easier.
Key idea
The GCF is the largest factor shared by every term. Factor it out using the distributive property:\[ab+ac=a(b+c).\]After you factor out the GCF, check again: the remaining factor may still be factorable.
Worked example
Example: Factor completely: \(9x^2+3x\).
The GCF is \(3x\). Factor it out:\[9x^2+3x=3x(3x+1).\]The binomial \((3x+1)\) does not factor further over the integers, so this is fully factored.
Try it
Try it 1: What is the fully factored form of \(8x^2+4x\)?
Hint: The GCF is \(4x\). After factoring it out, check if the remaining binomial factors again.
Try it 2: Factor completely: \(a^2b^2-4ab\).
Hint: The GCF is \(ab\). Factor it out first.
Summary
Always factor out the GCF first.
Then check for patterns or more factoring in what remains.
Patterns
Step 2: Use common factoring patterns
Learning goal: Recognize and factor the two biggest patterns: difference of squares and perfect square trinomials.
Key idea
Two patterns show up constantly:\[a^2-b^2=(a-b)(a+b)\]\[a^2\pm2ab+b^2=(a\pm b)^2\]If you see a binomial that looks like “square minus square,” use difference of squares. If you see a trinomial with a first and last term that are perfect squares and a middle term that matches \(\pm2ab\), it’s a perfect square trinomial.
Worked example
Example: Factor \(x^2-25\).
This is a difference of squares: \(x^2-25=x^2-5^2\). \[x^2-25=(x-5)(x+5).\]
Try it
Try it 1: What is the factorization of \(2x^2-18\)?
Hint: Factor out the GCF \(2\), then use difference of squares on \(x^2-9\).
Try it 2: What is the factorization of \(4x^2-12x+9\)?
Hint: \(4x^2=(2x)^2\) and \(9=3^2\). Check if the middle term matches \(-2(2x)(3)\).
Learning goal: Factor common quadratic trinomials quickly and accurately: \(x^2+bx+c\) and \(ax^2+bx+c\).
Key idea
For \(x^2+bx+c\), find two numbers that multiply to \(c\) and add to \(b\). For \(ax^2+bx+c\), one reliable method is the \(ac\) method: find numbers that multiply to \(ac\) and add to \(b\), split the middle term, then factor by grouping.
Worked example
Example: Factor \(x^2-3x-10\).
We need numbers that multiply to \(-10\) and add to \(-3\): \(-5\) and \(2\). \[x^2-3x-10=(x-5)(x+2).\]
Try it
Try it 1: What is the factorization of \(x^2+5x+6\)?
Hint: Look for two numbers that multiply to \(6\) and add to \(5\).
Try it 2: What is the factorization of \(6x^2+13x+6\)?
Hint: Check by multiplying your factors to see if the middle term becomes \(13x\).
Summary
For \(x^2+bx+c\): two numbers multiply to \(c\) and add to \(b\).
For \(ax^2+bx+c\): use the \(ac\) idea, then group, then factor completely.
Grouping
Factoring by grouping (four terms)
Learning goal: Factor four-term polynomials by grouping into pairs and factoring out a common binomial.
Key idea
Grouping works when you can split a polynomial into two groups that share a common factor, often a common binomial. A reliable process: (1) Group into pairs, (2) factor the GCF from each pair, (3) factor out the common binomial.
Worked example
Example: Factor by grouping: \(3x^2-3x+2x-2\).
Group the first two and last two terms:\[(3x^2-3x)+(2x-2).\]Factor each group:\[3x(x-1)+2(x-1).\]Now factor the common binomial \((x-1)\):\[( x-1 )(3x+2).\]
Try it
Try it 1: Factor by grouping: \(x^3+3x^2-9x-27\).
Hint: Factor \((x^3+3x^2)\) and \((-9x-27)\) separately, then factor again.
Try it 2: Factor by grouping: \(x^3+x^2-x-1\).
Hint: Group as \((x^3+x^2)+(-x-1)\), factor out \((x+1)\), then factor \(x^2-1\).
Summary
Grouping is best for four terms.
After factoring out a common binomial, keep factoring (like factoring \(x^2-1\)).
Factor Completely
Factor completely: repeated patterns and identities
Learning goal: Recognize when you can factor again (especially with difference of squares) and use common identities (like \(x^3-1\)).
Key idea
“Factor completely” means you keep going until nothing factors further over the integers. A common situation is a difference of squares inside a factor:\[x^4-1=(x^2)^2-1^2=(x^2-1)(x^2+1),\]and then \(x^2-1\) factors again. Also remember:\[x^3-1=(x-1)(x^2+x+1).\]
Worked example
Example: Factor completely: \(x^4-1\).
Start with difference of squares:\[x^4-1=(x^2-1)(x^2+1).\]Factor \(x^2-1\) again as a difference of squares:\[x^2-1=(x-1)(x+1).\]So the fully factored form is:\[x^4-1=(x-1)(x+1)(x^2+1).\]
Try it
Try it 1: What is the factorization of \(x^4-1\) (fully factored over the integers)?
Hint: Factor as a difference of squares, then check if any factor can be factored again.
Try it 2: What is the factorization of \(x^3-1\)?
Hint: Use the identity \(a^3-b^3=(a-b)(a^2+ab+b^2)\) with \(a=x\), \(b=1\).
Summary
When you factor, always ask: “Can any factor be factored again?”
Know the big identities: difference of squares and \(x^3-1\).
Check & Solve
Check your factoring and solve equations
Learning goal: Verify factoring by multiplying, then use factoring to solve equations using the zero product property.
Key idea
The fastest way to verify a factorization is to multiply your factors and confirm you get the original expression. To solve a factored equation, use the zero product property:\[(x-7)(x+7)=0 \Rightarrow x=7 \text{ or } x=-7.\]
Worked example
Example: Solve \(x^2-49=0\).
Factor as a difference of squares:\[x^2-49=(x-7)(x+7).\]Set each factor equal to zero:\[x-7=0 \Rightarrow x=7,\quad x+7=0 \Rightarrow x=-7.\]
Try it
Try it 1: Solve \(2x^2-8=0\).
Hint: Factor out the GCF \(2\), then factor \(x^2-4\) as a difference of squares.
Try it 2: What should you do first when factoring any polynomial?
Hint: The GCF step never hurts and often reveals the next pattern.
Summary
Multiply factors to check your work.
Use the zero product property to solve factored equations.
Applications & Big Picture
Why factoring techniques matter
Learning goal: Connect factoring to simplifying expressions, solving equations, and understanding functions - then finish with a final check.
Where factoring shows up
Simplifying rational expressions: factoring lets you cancel common factors safely (with domain restrictions).
Solving quadratics: factoring turns a quadratic into two linear equations.
Graphs and intercepts: factored form shows zeros and x-intercepts quickly.
Modeling and geometry: area/volume expressions often factor to reveal structure.
Worked example: simplify using factoring
Example: Simplify \(\dfrac{x^2-25}{x-5}\).
Factor the numerator:\[x^2-25=(x-5)(x+5).\]Cancel the common factor (but remember \(x≠ 5\)):\[\dfrac{(x-5)(x+5)}{x-5}=x+5,\quad x≠ 5.\]
Final check
Final 1: What is the factorization of \(9x^2-12x+4\)?
Hint: \(9x^2=(3x)^2\) and \(4=2^2\). Check the middle term \(-2(3x)(2)\).
Final 2: What is the factorization of \(x^2-2x-15\)?
Hint: Look for two numbers that multiply to \(-15\) and add to \(-2\).
Final recap
Use the same order every time: GCF → patterns → trinomials → grouping → factor completely.
Common patterns: difference of squares, perfect square trinomials, and \(x^3-1\).
Check by multiplying, then use factoring to solve equations and simplify expressions.
Next step: Close this lesson and try your quiz again. If you miss a question, reopen the book and review the page that matches the factoring technique you need.
Practice set
Factoring Techniques practice questions with instant score
Answer all 10 questions below, then get your final score and a mistake review at the end so you know exactly what to improve.
0/10answered
Question 1Not answered
What is the factored form of \(7x + 14\)?
Correct answer: D. \(7(x + 2)\)
Explanation: Factor out the GCF \(7\): \(7x + 14 = 7(x + 2)\).
Question 2Not answered
What is the factorization of \(2x^2 + 8x + 8\)?
Correct answer: B. \(2(x + 2)^2\)
Explanation: First factor out the GCF \(2\), then recognize a perfect-square trinomial: \(2(x^2 + 4x + 4) = 2(x + 2)^2\).
Question 3Not answered
What is the factored form of \(5x + 10\)?
Correct answer: B. \(5(x + 2)\)
Explanation: Factor out the GCF \(5\): \(5x + 10 = 5(x + 2)\).
Question 4Not answered
What is the factored form of \(6x + 9\)?
Correct answer: D. \(3(2x + 3)\)
Explanation: Factor out the GCF \(3\): \(6x + 9 = 3(2x + 3)\).
Question 5Not answered
What is the fully factored form of \(8x^2 + 4x\)?
Correct answer: B. \(4x(2x + 1)\)
Explanation: Factor out the GCF \(4x\): \(8x^2 + 4x = 4x(2x + 1)\).
Question 6Not answered
What is the factorization of \(x^2 - 9\)?
Correct answer: D. \((x - 3)(x + 3)\)
Explanation: Recognize a difference of squares: \(x^2 - 9 = (x - 3)(x + 3)\).
