Vectors & Vector Operations II Practice Quiz with a Step-by-Step Interactive Lesson
Use the question set below to practice vectors and vector operations at the next level: the cross product in \(\mathbb{R}^3\) (including right-hand rule direction), area of a parallelogram and area of a triangle via \(\|u\times v\|\), the scalar triple product (also called the mixed product) for volume of a parallelepiped, coplanar vectors and the condition \((u\times v)\cdot w=0\), vector projection and scalar projection (components along a direction), distance from a point to a line/axis and distance from a point to a plane, and the Gram-Schmidt process to build an orthonormal basis. If you want a refresher with worked examples, click Start lesson.
How this vectors practice works
- 1. Take the practice set: answer the vectors and vector operations II questions below.
- 2. Open the lesson (optional): review cross product and triple product geometry, projection and scalar component, distance formulas, and Gram-Schmidt orthogonalization.
- 3. Retry: return to the question set and apply the correct vector formulas immediately.
What you will learn in the vectors & vector operations II lesson
Cross product & area in \(\mathbb{R}^3\)
- Cross product computation: \(u\times v\) component formula and determinant form
- Perpendicular vectors and the right-hand rule direction
- Area: \(\|u\times v\|\) (parallelogram) and \(\dfrac12\|u\times v\|\) (triangle)
Scalar triple product, determinants & volume
- Scalar triple product: \((u\times v)\cdot w=\det[u\;v\;w]\)
- Volume of a parallelepiped: \(\left|(u\times v)\cdot w\right|\)
- Coplanarity test: \((u\times v)\cdot w=0\) (volume \(=0\))
Projection, scalar component & distances
- Vector projection: \(\mathrm{proj}_b a=\dfrac{a\cdot b}{b\cdot b}\,b\) and scalar projection: \(\mathrm{comp}_b a=\dfrac{a\cdot b}{\|b\|}\)
- Distance to a line/axis: \(\|a-\mathrm{proj}_d a\|\) (or \(\dfrac{\|a\times d\|}{\|d\|}\))
- Distance to a plane using a normal vector: \(\dfrac{|n\cdot a-d|}{\|n\|}\)
Gram-Schmidt & orthonormal bases
- Gram-Schmidt process: build an orthogonal then orthonormal set
- Orthogonal component: subtract projections step-by-step
- Why it matters: clean coordinates, stable geometry, and foundations for QR decomposition
Practice set
Vettori e operazioni vettoriali II practice questions with instant score
Answer all 10 questions below, then get your final score and a mistake review at the end so you know exactly what to improve.
Qual è un vettore normale unitario al piano generato da \((1,0,0)\) e \((0,1,0)\)?
Correct answer: C. \((0,0,1)\)
Explanation: Prodotto vettoriale = \((1,0,0)\times(0,1,0) = (0,0,1)\), che ha già norma unitaria.
Qual è il prodotto vettoriale dei vettori \((1,2,3)\) e \((4,5,6)\)?
Correct answer: A. \((-3,6,-3)\)
Explanation: Calcola \((2\cdot6 - 3\cdot5,\;3\cdot4 - 1\cdot6,\;1\cdot5 - 2\cdot4) = (12-15,\;12-6,\;5-8) = (-3,6,-3)\).
Qual è il prodotto misto scalare di \((1,0,0)\), \((0,1,0)\) e \((0,0,1)\)?
Correct answer: C. \(1\)
Explanation: Prodotto misto scalare = \((1,0,0)\cdot[(0,1,0)\times(0,0,1)] = (1,0,0)\cdot(1,0,0) = 1\).
Qual è il modulo del prodotto vettoriale di \((1,1,0)\) e \((1,-1,0)\)?
Correct answer: C. \(2\)
Explanation: Prodotto vettoriale = \((1,1,0)×(1,-1,0) = (0,0,-2)\); modulo = \(2\).
Qual è la proiezione di \((3,3,3)\) su \((1,1,1)\)?
Correct answer: D. \((3,3,3)\)
Explanation: Prodotto scalare = \(9\), denominatore = \(1+1+1=3\), fattore di scala = \(9/3=3\); proiezione = \((3,3,3)\).
Qual è il volume del parallelepipedo generato da \((1,0,0)\), \((0,2,0)\) e \((0,0,3)\)?
Correct answer: B. \(6\)
Explanation: Volume = \(|(1,0,0)\cdot[(0,2,0)\times(0,0,3)]| = |(1,0,0)\cdot(6,0,0)| = 6\).
I vettori \((1,2,3)\), \((2,4,6)\) e \((3,6,9)\) sono complanari?
Correct answer: B. Sì
Explanation: Sono multipli scalari, quindi il prodotto misto \((1,2,3)\cdot[(2,4,6)\times(3,6,9)] = 0\), dunque sono complanari.
Qual è il prodotto vettoriale di \((2,0,0)\) e \((0,0,3)\)?
Correct answer: D. \((0,-6,0)\)
Explanation: Prodotto vettoriale = \((2,0,0)×(0,0,3) = (0,-6,0)\).
Qual è il prodotto vettoriale di \((0,2,0)\) e \((0,0,4)\)?
Correct answer: A. \((8,0,0)\)
Explanation: Prodotto vettoriale = \((0,2,0)×(0,0,4) = (8,0,0)\).
Qual è il modulo del prodotto vettoriale di \((1,2,0)\) e \((0,0,1)\)?
Correct answer: B. \(2\)
Explanation: Prodotto vettoriale = \((1,2,0)×(0,0,1) = (2,0,0)\); modulo = \(2\).
Result
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