Vectors & Vector Operations II Practice Quiz with a Step-by-Step Interactive Lesson
Use the question set below to practice vectors and vector operations at the next level: the cross product in \(\mathbb{R}^3\) (including right-hand rule direction), area of a parallelogram and area of a triangle via \(\|u\times v\|\), the scalar triple product (also called the mixed product) for volume of a parallelepiped, coplanar vectors and the condition \((u\times v)\cdot w=0\), vector projection and scalar projection (components along a direction), distance from a point to a line/axis and distance from a point to a plane, and the Gram-Schmidt process to build an orthonormal basis. If you want a refresher with worked examples, click Start lesson.
How this vectors practice works
- 1. Take the practice set: answer the vectors and vector operations II questions below.
- 2. Open the lesson (optional): review cross product and triple product geometry, projection and scalar component, distance formulas, and Gram-Schmidt orthogonalization.
- 3. Retry: return to the question set and apply the correct vector formulas immediately.
What you will learn in the vectors & vector operations II lesson
Cross product & area in \(\mathbb{R}^3\)
- Cross product computation: \(u\times v\) component formula and determinant form
- Perpendicular vectors and the right-hand rule direction
- Area: \(\|u\times v\|\) (parallelogram) and \(\dfrac12\|u\times v\|\) (triangle)
Scalar triple product, determinants & volume
- Scalar triple product: \((u\times v)\cdot w=\det[u\;v\;w]\)
- Volume of a parallelepiped: \(\left|(u\times v)\cdot w\right|\)
- Coplanarity test: \((u\times v)\cdot w=0\) (volume \(=0\))
Projection, scalar component & distances
- Vector projection: \(\mathrm{proj}_b a=\dfrac{a\cdot b}{b\cdot b}\,b\) and scalar projection: \(\mathrm{comp}_b a=\dfrac{a\cdot b}{\|b\|}\)
- Distance to a line/axis: \(\|a-\mathrm{proj}_d a\|\) (or \(\dfrac{\|a\times d\|}{\|d\|}\))
- Distance to a plane using a normal vector: \(\dfrac{|n\cdot a-d|}{\|n\|}\)
Gram-Schmidt & orthonormal bases
- Gram-Schmidt process: build an orthogonal then orthonormal set
- Orthogonal component: subtract projections step-by-step
- Why it matters: clean coordinates, stable geometry, and foundations for QR decomposition
Practice set
Vectoren en vectorbewerkingen II practice questions with instant score
Answer all 10 questions below, then get your final score and a mistake review at the end so you know exactly what to improve.
Wat is een eenheidsnormaalvector op het vlak opgespannen door \((1,0,0)\) en \((0,1,0)\)?
Correct answer: C. \((0,0,1)\)
Explanation: Kruisproduct = \((1,0,0)\times(0,1,0) = (0,0,1)\), en die heeft al lengte 1.
Wat is het kruisproduct van de vectoren \((1,2,3)\) en \((4,5,6)\)?
Correct answer: A. \((-3,6,-3)\)
Explanation: Bereken \((2\cdot6 - 3\cdot5,\;3\cdot4 - 1\cdot6,\;1\cdot5 - 2\cdot4) = (12-15,\;12-6,\;5-8) = (-3,6,-3)\).
Wat is het scalair drievoudig product van \((1,0,0)\), \((0,1,0)\) en \((0,0,1)\)?
Correct answer: C. \(1\)
Explanation: Scalair drievoudig product = \((1,0,0)\cdot[(0,1,0)\times(0,0,1)] = (1,0,0)\cdot(1,0,0) = 1\).
Wat is de grootte van het kruisproduct van \((1,1,0)\) en \((1,-1,0)\)?
Correct answer: C. \(2\)
Explanation: Kruisproduct = \((1,1,0)×(1,-1,0) = (0,0,-2)\); grootte = \(2\).
Wat is de projectie van \((3,3,3)\) op \((1,1,1)\)?
Correct answer: D. \((3,3,3)\)
Explanation: Inproduct = \(9\), noemer = \(1+1+1=3\), schaalfactor = \(9/3=3\); projectie = \((3,3,3)\).
Wat is het volume van het parallellepipedum opgespannen door \((1,0,0)\), \((0,2,0)\) en \((0,0,3)\)?
Correct answer: B. \(6\)
Explanation: Volume = \(|(1,0,0)\cdot[(0,2,0)\times(0,0,3)]| = |(1,0,0)\cdot(6,0,0)| = 6\).
Liggen de vectoren \((1,2,3)\), \((2,4,6)\) en \((3,6,9)\) in hetzelfde vlak?
Correct answer: B. Ja
Explanation: Ze zijn scalaire veelvouden, dus het scalair drievoudig product \((1,2,3)\cdot[(2,4,6)\times(3,6,9)] = 0\), dus liggen ze in hetzelfde vlak.
Wat is het kruisproduct van \((2,0,0)\) en \((0,0,3)\)?
Correct answer: D. \((0,-6,0)\)
Explanation: Kruisproduct = \((2,0,0)×(0,0,3) = (0,-6,0)\).
Wat is het kruisproduct van \((0,2,0)\) en \((0,0,4)\)?
Correct answer: A. \((8,0,0)\)
Explanation: Kruisproduct = \((0,2,0)×(0,0,4) = (8,0,0)\).
Wat is de grootte van het kruisproduct van \((1,2,0)\) en \((0,0,1)\)?
Correct answer: B. \(2\)
Explanation: Kruisproduct = \((1,2,0)×(0,0,1) = (2,0,0)\); grootte = \(2\).
Result
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